M

Arc.Create

Description:
Creates a new geometric arc object based on three points.

Overloads (3):

Create(XYZ,Double,Double,Double,XYZ,XYZ)

Create(XYZ,XYZ,XYZ)

public static Arc Create(
	XYZ end0,
	XYZ end1,
	XYZ pointOnArc
)

Public Shared Function Create ( _
	end0 As XYZ, _
	end1 As XYZ, _
	pointOnArc As XYZ _
) As Arc

public:
static Arc^ Create(
	XYZ^ end0, 
	XYZ^ end1, 
	XYZ^ pointOnArc
)

Autodesk.Revit.DB.XYZ

end0

The start point of the arc.
Autodesk.Revit.DB.XYZ

end1

The end point of the arc.
Autodesk.Revit.DB.XYZ

pointOnArc

A point on the arc.

Return Value The new arc. The new arc.

// Create a new arc using two ends and a point on the curve
XYZ end0 = new XYZ(1, 0, 0);    // start point of the arc
XYZ end1 = new XYZ(10, 10, 10); // end point of the arc
XYZ pointOnCurve = new XYZ(10, 0, 0);   // point along arc

Arc arc = Arc.Create(end0, end1, pointOnCurve);

' Create a new arc using two ends and a point on the curve
Dim end0 As New XYZ(1, 0, 0)
' start point of the arc
Dim end1 As New XYZ(10, 10, 10)
' end point of the arc
Dim pointOnCurve As New XYZ(10, 0, 0)
' point along arc
Dim arc__1 As Arc = Arc.Create(end0, end1, pointOnCurve)

Autodesk.Revit.Exceptions.ArgumentNullException

A non-optional argument was NULL
Autodesk.Revit.Exceptions.ArgumentsInconsistentException

The vectors end0 and end1 are coincident. -or- The vectors end0 and pointOnArc are coincident. -or- The vectors end1 and pointOnArc are coincident. -or- Cannot create an arc. -or- Curve length is too small for Revit's tolerance (as identified by Application.ShortCurveTolerance).